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If triangleH(f) (C(2)H(5)-S-C(2)H(5))=-1...

If `triangleH_(f) (C_(2)H_(5)-S-C_(2)H_(5))=-147` kJ/mole and
`triangleH_(f) (C_(2)H_(5)-S-S-C_(2)H_(5))=-202` Kj/mole and
`triangleH_(f) (S) (g)=+ 223 kJ/mole then the S-S bond energy will be

A

168 kJ

B

126 kJ

C

278 kJ

D

572 kJ

Text Solution

AI Generated Solution

The correct Answer is:
To find the S-S bond energy using the given enthalpies of formation, we can follow these steps: ### Step 1: Write the Reaction We need to consider the formation of the compound \( C_2H_5-S-S-C_2H_5 \) from \( C_2H_5-S-C_2H_5 \) and sulfur (S). The reaction can be written as: \[ C_2H_5-S-C_2H_5 + S \rightarrow C_2H_5-S-S-C_2H_5 \] ### Step 2: Use the Enthalpy of Formation Values We are given the following values: - \( \Delta H_f (C_2H_5-S-C_2H_5) = -147 \, \text{kJ/mol} \) - \( \Delta H_f (C_2H_5-S-S-C_2H_5) = -202 \, \text{kJ/mol} \) - \( \Delta H_f (S) = +223 \, \text{kJ/mol} \) ### Step 3: Calculate the Change in Enthalpy for the Reaction Using the enthalpy of formation values, we can calculate the change in enthalpy (\( \Delta H \)) for the reaction: \[ \Delta H = \Delta H_f (\text{products}) - \Delta H_f (\text{reactants}) \] Substituting the values we have: \[ \Delta H = \Delta H_f (C_2H_5-S-S-C_2H_5) - \Delta H_f (C_2H_5-S-C_2H_5) - \Delta H_f (S) \] \[ \Delta H = (-202) - (-147) - (223) \] Calculating this gives: \[ \Delta H = -202 + 147 - 223 = -278 \, \text{kJ/mol} \] ### Step 4: Relate the Change in Enthalpy to Bond Energies The change in enthalpy can also be expressed in terms of bond energies: \[ \Delta H = \text{Bond energy of reactants} - \text{Bond energy of products} \] For our case, the bond energy of reactants includes the bond energy of the S-S bond we want to find. Therefore, we can express it as: \[ -278 = \text{Bond energy of S} - \text{Bond energy of S-S} \] Where the bond energy of sulfur (S) is given as \( +223 \, \text{kJ/mol} \). ### Step 5: Solve for the S-S Bond Energy Rearranging the equation: \[ \text{Bond energy of S-S} = \text{Bond energy of S} + 278 \] Substituting the known value: \[ \text{Bond energy of S-S} = 223 + 278 = 501 \, \text{kJ/mol} \] ### Final Answer The bond energy of the S-S bond is \( 501 \, \text{kJ/mol} \). ---
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