Home
Class 12
CHEMISTRY
If K(1) represents the equilibrium const...

If `K_(1)` represents the equilibrium constant for reaction: `H_(2)+I_(2)hArr2HI & K_(2)" for "(1)/(2)H_(2)+(1)/(2)I_(2)hArr HI` the relation between `K_(1)& K_(2)` would be

A

`K_(1)xxK_(2)=1`

B

`sqrt(K_(1))xxK_(2)=1`

C

`sqrt(K_(1))=K_(2)`

D

`sqrt(K_(1))=sqrt(K_(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

The equilibrium constant for N_(2)(g)+O_(2)(g)hArr2NO "is" K_(1) and that for NO(g)hArr(1)/(2)N_(2)(g)+(1)/(2)O_(2)(g) is K_(2). K_(1) "and" K_(2) will be related as

If the equilibrium constant of the reaction 2HI hArrH_(2) + I_(2) is 0.25 , then the equilibrium constant of the reaction H_(2) + I_(2)hArr2HI would be

The value of equilibrium constant of the reaction. HI(g)hArr(1)/(2)H_2(g)+(1)/(2)I_2(g)is 8.0 The equilibrium constant of the reaction. H_2(g)+I_2(g)hArr2HI(g) will be

What will be the equilibrium constant at 717K for the reaction 2HI(g) hArr H_2(g) +I_2(g) if K for H_2(g) +I_2(g) hArr 2HI at 717 K is 50.

The equilibrium constant for the reversible reaction N_(2)+3H_(2) hArr 2NH_(3) is K and for the reaction (1)/(2) N_(2)+(3)/(2) H_(2) hArr NH_(3) , the equilibrium constant is K',.K and K' will be related as

Equilibrium constant for the reaction: H_(2)(g) +I_(2) (g) hArr 2HI(g) is K_(c) = 50 at 25^(@)C The standard Gibbs free enegry change for the reaction will be:

If the equilibrium constant for the reaction A_(2)+B_(2) hArr 2AB is K, then the backward reaction, AB hArr 1/2 A_(2)+1/2 B_(2) the equilibrium constant is 1//K .