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In a reaction A+BhArrC+D the rate consta...

In a reaction `A+BhArrC+D` the rate constant of forward reaction & backward reaction is `K_(1)` and `K_(2)` then the equilibrium constant `(K)` for reaction is expressed as:

A

`K_(C)=(K_(2))/(K_(1))`

B

`K_(C)=(K_(1))/(K_(2))`

C

`K_(C)=K_(1)xxK_(2)`

D

`K_(C)=K_(1)+K_(2)`

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The correct Answer is:
B
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