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K(1) and K(2) are equilibrium constants ...

`K_(1)` and `K_(2)` are equilibrium constants for reaction (i) and (ii)
`N_(2)(g)+O_(2)(g) hArr 2NO(g)` …(i)
`NO(g) hArr 1//2 N_(2)(g)+1//2O_(2)(g)` …(ii)
then,

A

`K_(1)=((1)/(K_(2)))^(2)`

B

`K_(1)=(K_(2)^(2)`

C

`K_(1)=((1)/(K_(2)))`

D

`K_(1)=(K_(2))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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