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{:("For the reaction",PCl(5)hArrPCl(3)+C...

`{:("For the reaction",PCl_(5)hArrPCl_(3)+Cl_(2)),("Initial moles are"," a b c"):}`
If `alpha` is the degree of dissociation and P is the total pressure. The partial pressure of `PCl_(3)` is

A

`(b+a alpha)/(a+b+c+a alpha)"P atm"`

B

`(a+a alpha)/(a+b+c+a alpha)"P atm"`

C

`(a(a -alpha))/(a+b+c+a alpha)"P atm"`

D

`(a+b+c+a alpha)/(b+a alpha)"P atm"`

Text Solution

AI Generated Solution

The correct Answer is:
To find the partial pressure of \( PCl_3 \) in the reaction \( PCl_5 \rightleftharpoons PCl_3 + Cl_2 \) with given initial moles and degree of dissociation, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Initial Moles**: - Let the initial moles of \( PCl_5 \) be \( a \). - Let the initial moles of \( PCl_3 \) be \( b \). - Let the initial moles of \( Cl_2 \) be \( c \). 2. **Define Degree of Dissociation**: - Let \( \alpha \) be the degree of dissociation of \( PCl_5 \). This means that \( \alpha \) fraction of \( PCl_5 \) dissociates. 3. **Calculate Moles at Equilibrium**: - At equilibrium, the moles of each species will be: - Moles of \( PCl_5 \) = \( a - a\alpha = a(1 - \alpha) \) - Moles of \( PCl_3 \) = \( b + a\alpha \) - Moles of \( Cl_2 \) = \( c + a\alpha \) 4. **Calculate Total Moles at Equilibrium**: - The total moles at equilibrium will be: \[ \text{Total moles} = (a(1 - \alpha)) + (b + a\alpha) + (c + a\alpha) \] Simplifying this gives: \[ \text{Total moles} = a + b + c + a\alpha \] 5. **Calculate Mole Fraction of \( PCl_3 \)**: - The mole fraction of \( PCl_3 \) is given by: \[ \text{Mole fraction of } PCl_3 = \frac{\text{Moles of } PCl_3}{\text{Total moles}} = \frac{b + a\alpha}{a + b + c + a\alpha} \] 6. **Use Dalton's Law to Find Partial Pressure**: - According to Dalton's Law, the partial pressure of \( PCl_3 \) is: \[ P_{PCl_3} = \text{Mole fraction of } PCl_3 \times P \] - Substituting the mole fraction we found: \[ P_{PCl_3} = \left(\frac{b + a\alpha}{a + b + c + a\alpha}\right) \times P \] ### Final Expression: The partial pressure of \( PCl_3 \) is: \[ P_{PCl_3} = \frac{(b + a\alpha)}{(a + b + c + a\alpha)} \times P \]
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