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Select the incorrect statement:...

Select the incorrect statement:

A

pH of 500 ml 0.001 N `HNO_(3)` is 3.0

B

pH of 500 ml 0.001 N `HNO_(3)` is 4 - log 5

C

pH of 20 ml decinormal HCI solution is 1.0

D

pH of 100 ml 0.01 N NaCI solution is = 7.0

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of selecting the incorrect statement regarding the pH of various solutions, we will analyze each statement step by step. ### Step 1: Analyze the first statement **Statement:** The pH of 500 ml of 0.001 normal HNO3 is 3. **Solution:** 1. **Determine the concentration of H⁺ ions:** HNO3 is a strong acid and dissociates completely. Therefore, the concentration of H⁺ ions is the same as the concentration of HNO3. 2. **Given:** Normality (N) = 0.001 N, which is also the same as molarity (M) since HNO3 has an n-factor of 1. 3. **Calculate pH:** - pH = -log[H⁺] - pH = -log(0.001) = -log(10^-3) = 3. 4. **Conclusion:** This statement is correct. ### Step 2: Analyze the second statement **Statement:** The pH of 500 ml of 0.001 HNO3 is 4 - log 5. **Solution:** 1. **From Step 1:** We already calculated the pH of 0.001 HNO3 to be 3. 2. **Evaluate the statement:** - 4 - log 5 does not equal 3. - log 5 is approximately 0.699, so 4 - log 5 ≈ 4 - 0.699 ≈ 3.301, which is not equal to 3. 3. **Conclusion:** This statement is incorrect. ### Step 3: Analyze the third statement **Statement:** The pH of 20 ml of 0.1 normal HCl is 1. **Solution:** 1. **Determine the concentration of H⁺ ions:** HCl is also a strong acid and dissociates completely. 2. **Given:** Normality (N) = 0.1 N, which is the same as molarity (M) since HCl has an n-factor of 1. 3. **Calculate pH:** - pH = -log[H⁺] - pH = -log(0.1) = -log(10^-1) = 1. 4. **Conclusion:** This statement is correct. ### Step 4: Analyze the fourth statement **Statement:** The pH of 100 ml of 0.1 NaCl solution is 7. **Solution:** 1. **Understanding NaCl:** NaCl is a neutral salt formed from a strong acid (HCl) and a strong base (NaOH). 2. **pH of neutral salts:** The pH of a solution of NaCl is neutral (pH = 7) because it does not affect the concentration of H⁺ or OH⁻ ions in water. 3. **Conclusion:** This statement is correct. ### Final Conclusion After analyzing all statements: - The first statement is correct. - The second statement is incorrect. - The third statement is correct. - The fourth statement is correct. Thus, the **incorrect statement** is the second one: "The pH of 500 ml of 0.001 HNO3 is 4 - log 5."
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