When 0.1 mole of `NH_(3)` is dissolved in water to make 1.0 L of solution , the `[OH^(-)]` of solution is `1.34 xx 10^(-3)`M. Calculate `K_(b)` for `NH_(3)`.

Options

A. `1.8 xx 10^(-5)`
B. `2.8 xx 10^(-5)`
C. `1.8 xx 10^(-7)`
D. `2.8 xx 10^(-7)`

Answer

A