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The number of hydroxyl ions in 100 mL of...

The number of hydroxyl ions in 100 mL of a solution having pH 10 is

A

`1 xx 10^(4)`

B

`3.012 xx 10^(4)`

C

`6.02 xx 10^(18)`

D

`6.023 xx 10^(19)`

Text Solution

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The correct Answer is:
To find the number of hydroxyl ions (OH⁻) in 100 mL of a solution with a pH of 10, we can follow these steps: ### Step 1: Calculate the concentration of hydrogen ions (H⁺) The pH of a solution is related to the concentration of hydrogen ions by the formula: \[ \text{pH} = -\log[H^+] \] To find the concentration of H⁺ ions, we can rearrange this formula: \[ [H^+] = 10^{-\text{pH}} = 10^{-10} \] ### Step 2: Calculate the concentration of hydroxyl ions (OH⁻) We can use the ion product of water (K_w) to find the concentration of hydroxyl ions. At 25°C, \(K_w = 10^{-14}\): \[ K_w = [H^+][OH^-] \] We can rearrange this to find [OH⁻]: \[ [OH^-] = \frac{K_w}{[H^+]} = \frac{10^{-14}}{10^{-10}} = 10^{-4} \] ### Step 3: Convert the concentration of hydroxyl ions to millimoles Since we want to find the number of hydroxyl ions in 100 mL, we first convert the concentration from molarity to millimolarity: \[ \text{Millimolarity} = [OH^-] \times 1000 = 10^{-4} \times 1000 = 10^{-1} \text{ mM} \] ### Step 4: Calculate the number of moles of hydroxyl ions in 100 mL Now, we can find the number of moles of hydroxyl ions in 100 mL: \[ \text{Number of moles} = \text{Millimolarity} \times \text{Volume in L} = 10^{-1} \times 0.1 = 10^{-2} \text{ moles} \] ### Step 5: Convert moles to number of hydroxyl ions To find the total number of hydroxyl ions, we multiply the number of moles by Avogadro's number (\(6.022 \times 10^{23}\)): \[ \text{Number of OH}^- = 10^{-2} \times 6.022 \times 10^{23} = 6.022 \times 10^{21} \] ### Final Answer The number of hydroxyl ions in 100 mL of a solution having pH 10 is approximately \(6.022 \times 10^{21}\). ---
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