TiCl has structure similar as CsCl, the co-ordination number of `Ti^(+)` will be:

Options

A. 4
B. 6
C. 10
D. 8

Answer

To determine the coordination number of \( \text{Ti}^+ \) in \( \text{TiCl} \) which has a structure similar to \( \text{CsCl} \), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure**:
- The structure of \( \text{TiCl} \) is similar to that of \( \text{CsCl} \). In \( \text{CsCl} \), the \( \text{Cs}^+ \) ions are located at the body center of the cube, while the \( \text{Cl}^- \) ions are located at the corners of the cube.

2. **Identify the Position of Ions**:
- In \( \text{TiCl} \), \( \text{Ti}^+ \) will occupy the body center of the cubic unit cell, and \( \text{Cl}^- \) ions will be located at the eight corners of the cube.

3. **Determine Neighboring Ions**:
- The coordination number is defined as the number of nearest neighbor atoms surrounding a central atom. In this case, we need to find how many \( \text{Cl}^- \) ions are nearest to the \( \text{Ti}^+ \) ion.

4. **Count the Corner Ions**:
- There are 8 corners in a cube, and each corner is occupied by a \( \text{Cl}^- \) ion. Therefore, \( \text{Ti}^+ \) has 8 \( \text{Cl}^- \) ions as its nearest neighbors.

5. **Conclusion**:
- The coordination number of \( \text{Ti}^+ \) in \( \text{TiCl} \) is 8.

### Final Answer:
The coordination number of \( \text{Ti}^+ \) in \( \text{TiCl} \) is **8**.

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