Methyl amine on reaction with Hinsberg reagent gives :

Options

A. N-methyl benzamide
B. N-methyl benzene sulphonamide
C. Methyl Isothiocyanata
D. N-methyl acetamide

Answer

To solve the question, "Methyl amine on reaction with Hinsberg reagent gives," we need to follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are methyl amine (CH₃NH₂) and Hinsberg reagent, which is benzene sulfonyl chloride (C₆H₅SO₂Cl).

### Step 2: Understand the Reaction Mechanism
Hinsberg reagent reacts with amines to form sulfonamides. Methyl amine is a primary amine, and it will react with benzene sulfonyl chloride through nucleophilic substitution.

### Step 3: Nucleophilic Attack
The nitrogen atom in methyl amine has a lone pair of electrons, which will attack the electrophilic sulfur atom in benzene sulfonyl chloride. This results in the formation of an intermediate.

### Step 4: Formation of N-Methyl Sulfonamide
The reaction proceeds with the formation of N-methyl sulfonamide. The structure of N-methyl sulfonamide can be represented as CH₃NH-SO₂C₆H₅. During this process, the chloride ion (Cl⁻) is released.

### Step 5: Solubility in Alkali
The product, N-methyl sulfonamide, is soluble in alkali (basic conditions). This is a characteristic of sulfonamides.

### Final Answer
Methyl amine on reaction with Hinsberg reagent gives N-methyl sulfonamide (CH₃NH-SO₂C₆H₅).

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