Aniline ` underset( 50 ^@ C ) overset( H_2 O_2 ) to A ,[A] ` is :

Options

A. Nitrosobenzne
B. nitro aniline
C. aniline
D. phenol

Answer

To solve the question regarding the reaction of aniline with hydrogen peroxide (H₂O₂) at 50°C, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant in this case is aniline, which has the chemical formula C₆H₅NH₂.

2. **Understand the Reaction Conditions**: The reaction is conducted at a temperature of 50°C and involves hydrogen peroxide (H₂O₂) as a reagent.

3. **Recognize the Role of H₂O₂**: Hydrogen peroxide acts as an oxidizing agent in this reaction. This means it will facilitate the oxidation of aniline.

4. **Identify the Functional Group Change**: In this reaction, the amino group (–NH₂) of aniline is oxidized to a nitro group (–NO₂).

5. **Determine the Product**: The oxidation of aniline (C₆H₅NH₂) leads to the formation of nitrobenzene (C₆H₅NO₂).

6. **Write the Final Equation**: The overall reaction can be summarized as:
\[ \text{C₆H₅NH₂} + \text{H₂O₂} \rightarrow \text{C₆H₅NO₂} + \text{H₂O} \]

### Conclusion:
The compound A formed from the reaction of aniline with H₂O₂ at 50°C is nitrobenzene (C₆H₅NO₂).

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