Oxidation of aniline with `H_2 O_2 ` gives :

Options

A. O-nitroaniline
B. N- Nitroso aniline
C. Nitrosobenzne
D. O-Benzoquinone

Answer

To solve the question regarding the oxidation of aniline with hydrogen peroxide (H₂O₂), we will follow these steps:

### Step 1: Identify the Reactants
We start with aniline, which has the chemical formula C₆H₅NH₂. The oxidizing agent in this reaction is hydrogen peroxide (H₂O₂).

### Step 2: Understand the Oxidation Process
Aniline (C₆H₅NH₂) can undergo oxidation when reacted with H₂O₂. The oxidation process involves the conversion of the amino group (-NH₂) into different nitrogen-containing functional groups.

### Step 3: Reaction with One Mole of H₂O₂
When aniline reacts with one mole of H₂O₂, it gets oxidized to form N-phenylhydroxyamine (C₆H₅NHOH). This compound is formed due to the introduction of a hydroxyl group (-OH) to the nitrogen atom.

### Step 4: Reaction with Two Moles of H₂O₂
If we continue the oxidation process by adding a second mole of H₂O₂, the N-phenylhydroxyamine can be further oxidized to form nitrosobenzene (C₆H₅NO), where the nitrogen is now in the nitroso (-NO) form.

### Step 5: Reaction with Three Moles of H₂O₂
Finally, when we add a third mole of H₂O₂, the nitrosobenzene undergoes further oxidation to yield nitrobenzene (C₆H₅NO₂). This is the final product of the complete oxidation of aniline with three moles of hydrogen peroxide.

### Conclusion
Thus, the oxidation of aniline with H₂O₂ can lead to the formation of nitrobenzene after three moles of H₂O₂ are used. However, if we only consider two moles of H₂O₂, we will obtain nitrosobenzene.

### Final Answer
The oxidation of aniline with H₂O₂ gives nitrosobenzene (C₆H₅NO) when two moles of H₂O₂ are used.

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