The bromination of aniline in presence of water produces :

Options

A. 2-Bromoaniline
B. 4- bromoanilne
C. 2,4,6- Tribromoaniline
D. 2,6 -dibromaniline.

Answer

To solve the question regarding the bromination of aniline in the presence of water, we can follow these steps:

### Step 1: Understand the Structure of Aniline
Aniline is an aromatic amine with the formula C6H5NH2. The NH2 group is attached to a benzene ring.

### Step 2: Identify the Nature of the Reaction
The bromination of aniline is an electrophilic aromatic substitution reaction. In this reaction, bromine (Br2) acts as an electrophile.

### Step 3: Determine the Effects of the NH2 Group
The NH2 group is an activating group due to its +M (mesomeric) effect, which increases the electron density on the benzene ring. It also has a -I (inductive) effect, but the +M effect dominates. This means that the bromination will occur predominantly at the ortho and para positions relative to the NH2 group.

### Step 4: Analyze the Reaction Conditions
When bromination occurs in the presence of water, it is considered vigorous bromination. The presence of water does not inhibit the reaction; instead, it allows for multiple bromine atoms to be added to the benzene ring.

### Step 5: Predict the Product
Due to the strong activating effect of the NH2 group and the vigorous conditions, bromination will occur at all three positions: ortho (2-position), para (4-position), and meta (6-position). Therefore, the product will be 2,4,6-tribromoaniline.

### Step 6: Write the Final Answer
The bromination of aniline in the presence of water produces **2,4,6-tribromoaniline**.

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