When aniline is treated with benzene diazonium chloride at low temperature in weakly medium , the final product obtained is :

Options

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Answer

To solve the question of what product is obtained when aniline is treated with benzene diazonium chloride at low temperature in a weakly acidic medium, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are aniline (C6H5NH2) and benzene diazonium chloride (C6H5N2Cl).

2. **Understand the Reaction Type**:
- This reaction is known as a coupling reaction. In this process, the diazonium salt reacts with an aromatic amine (aniline) to form an azo compound.

3. **Reaction Mechanism**:
- At low temperatures and in a weakly acidic medium, the diazonium ion (C6H5N2+) reacts with the aniline. The nitrogen from the diazonium ion is highly electrophilic and will react with the nucleophilic amine group of aniline.

4. **Formation of the Product**:
- The hydrogen atom on the para position of the aniline is replaced by the diazonium group (N2). The reaction can be represented as follows:
- C6H5NH2 + C6H5N2Cl → C6H5-N=N-C6H4-NH2 + HCl
- Here, the product formed is para-aminoazobenzene (C6H5-N=N-C6H4-NH2).

5. **Final Product Description**:
- The final product is a compound known as para-aminoazobenzene, which is a pale yellow dye.

### Final Answer:
The final product obtained when aniline is treated with benzene diazonium chloride at low temperature in a weakly acidic medium is **para-aminoazobenzene**.

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