2-4 dinitroaniline is treated with ` NaNO_(2)` and dilute HCI at 280 K followed by reaction with anisole , forming a coloured compound . The structure of this coloured compound would be :

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Answer

To solve the problem, we will follow these steps:

### Step 1: Understand the Reactants
We start with 2,4-dinitroaniline, which has the following structure:
- An aniline (C6H5NH2) core with two nitro (NO2) groups at the 2 and 4 positions on the benzene ring.

### Step 2: Diazotization Reaction
When 2,4-dinitroaniline is treated with sodium nitrite (NaNO2) and dilute hydrochloric acid (HCl) at low temperatures (280 K), a diazotization reaction occurs. This converts the amino group (-NH2) into a diazonium group (-N2+Cl-), resulting in the formation of 2,4-dinitrobenzenediazonium chloride.

### Step 3: Reaction with Anisole
Next, we react the diazonium salt with anisole (C6H5OCH3). Anisole has a methoxy group (-OCH3) that is an electron-donating group. This group will direct the electrophilic substitution to the ortho and para positions of the benzene ring.

### Step 4: Electrophilic Substitution
Due to the electron-donating nature of the methoxy group, the diazonium ion will preferentially attack the para position relative to the methoxy group. The resulting product will be a para-substituted compound where the diazonium group replaces a hydrogen atom at the para position of the anisole.

### Step 5: Structure of the Coloured Compound
The final structure of the coloured compound will have:
- The original anisole structure with a para-diazophenyl group (C6H4N2) and the methoxy group (OCH3) attached to the benzene ring.
- The nitro groups (NO2) will remain at the 2 and 4 positions of the benzene ring.

### Final Structure
The final structure can be represented as:
- A benzene ring with a para-diazophenyl group and a methoxy group, along with nitro groups at the 2 and 4 positions.