`CH_3 NH_2 overset( "excess " CH_3 Cl) to (X ) underset( "moist ") overset( Ag_2 O) to (Y ) overset ( Y ) overset( Delta ) to (Z) ` the final product (z) is :

Options

A. `(CH_3)_3 N`
B. `(CH_3)_(4)^(+)Cl^(-)`
C. `(CH_3)_4^(+)OH^-`
D. `(CH_3)_2NH`

Answer

To solve the given problem step by step, we will analyze the reactions involving methyl amine (CH₃NH₂) and the reagents provided.

### Step 1: Reaction of Methyl Amine with Excess Methyl Chloride
- **Reactants:** CH₃NH₂ (methyl amine) + CH₃Cl (methyl chloride)
- **Process:** Methyl amine acts as a nucleophile and attacks the methyl chloride. The chlorine atom (Cl) leaves, forming HCl as a byproduct.
- **First Reaction:**
- CH₃NH₂ + CH₃Cl → CH₃NH(CH₃) + HCl
- **Second Reaction (due to excess CH₃Cl):**
- CH₃NH(CH₃) + CH₃Cl → (CH₃)₂N(CH₃) + HCl
- **Final Product after this step (X):** (CH₃)₃N (trimethylamine) + 2 HCl

### Step 2: Reaction of Trimethylamine with Moist Silver Oxide
- **Reactants:** (CH₃)₃N + Ag₂O (moist)
- **Process:** The moist silver oxide reacts with the chloride ions (Cl⁻) produced in the previous step to form AgCl and water. The quaternary ammonium salt (trimethylamine) can undergo hydrolysis.
- **Reaction:**
- (CH₃)₃N + Cl⁻ + Ag₂O → (CH₃)₃N + AgCl + H₂O
- **Final Product after this step (Y):** (CH₃)₃N (still trimethylamine, but now in a solution with AgCl)

### Step 3: Heating the Product Y
- **Reactants:** (CH₃)₃N
- **Process:** When heated, trimethylamine can undergo a reaction to form a product through elimination or rearrangement.
- **Reaction:**
- (CH₃)₃N → (CH₃)₃C (tert-butylamine) + NH₃ (ammonia)
- **Final Product after this step (Z):** (CH₃)₃C (tert-butylamine)

### Conclusion
The final product (Z) after all the reactions is **tert-butylamine (C₄H₉N)**.