The standard reduction potential of `Zn^(2+)|Zn` and `Cu^(2+)|Cu` are `-0.76V` and `+0.34` V respectively. What is the cell e.m.f (in V) of the following cell?
`((RT)/(F)=0.059)`
`Zn//Zn^(2+)" "(0.05M)//Cu^(2+)(0.005M)//Cu`

The standard electrode potential of Zn^(2+)|ZnandCu^(2+)|Cu are - 0.76 and 0.34 V respectively . The standard e.m.f. of the cell is :

The standard reduction potential of Zn is -0.76V and that of Cu is +0.34V . What do they indicate?

Fill in the blanks : The standard reduction potentials of Cu and Zn are 0.34V and -0.76 V respectively. The emf of the cell formed by combining the two electrodes will be ………….

The standard reducution potentials of Zn^(2+)|Zn,Cu^(2+)|Cu and Ag^(+)|Ag are respectively -0.76,0.34 and 0.8V . The following cells were constructed. Zn|Zn^(2+)"||"Cu^(2+)|Cu Zn|Zn^(2+)"||"Ag^(+)|Ag Cu|Cu^(2+)"||"Ag^(+)|Ag What is the correct order E_("cell")^(0) of these cell?

The standard reducution potentials of Zn^(2+)|Zn,Cu^(2+)|Cu and Ag^(+)|Ag are respectively -0.76,0.34 and 0.8V . The following cells were constructed. Zn|Zn^(2+)"||"Cu^(2+)|Cu Zn|Zn^(2+)"||"Ag^(+)|Ag Cu|Cu^(2+)"||"Ag^(+)|Ag What is the correct order E_("cell")^(0) of these cell?

The standard reduction potentials of Zn^(2+)//Zn,Cu^(2+)//Cu and Ag^(+)//Ag are respectively -0.78, 0.34 and 0.8 V. The following cells were constructed: (1) Zn |Zn^(2+)|| Cu^(2+)|Cu (2) Zn |Zn^(2+)|| Ag^(+)|Ag (3) Cu |Cu^(2+)|| Ag^(+)|Ag What is the correct order of of these cells?

E^@ values of Zn^(2+), Zn and Cu^(2+), Cu are respectively -0.76 V and + 0.34 . Calculate the EMF of the cell Zn//Zn^(2+) (0.1M)"//"Cu^(2+)(0.1 M)//Cu .