[" Electric field in a region is given by "vec E=-4xhat i+6yhat j" .Then find the charge enclosed in "],[" the cube of side "1m" oriented as shown in the diagram."]

Electric field in a region is given by vec(E)=-4xhat(i)+6yhat(j) . The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by alpha in_(0) . Find the value of alpha .

Electric field in a region is given by vec(E)=-4xhat(i)+6yhat(j) . The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by alpha in_(0) . Find the value of alpha .

Electric field in a region is given by vec(E)=-4xhat(i)+6yhat(j) . The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by alpha in_(0) . Find the value of alpha .

Electric field in a region of space is given by vec E=ayhat i+axhat j then

If the electric field in a region is given by vec(E) = 5 hat(i) + 4 hat(j)+ 9 hat(K) , then the electric flux through a surface of area 20 units lying in the y-z plane will be

Electric field in a region of space is given by vec E=ayhat i+axhat j then (A) shape of field lines will be hyperbola (B) shape of field lines will be straight lines (C) shape of equipotential surface will be rectangular hyperbola

The electric potential V("x") in a region around the origin is given by V"(x)" = 4x^(2) volts. The electric charge enclosed in a cube of 1 m side with its centre at the origin is (in coulomb

The electric field in a certain region is given by vec(E) = ((K)/(x^(3)))vec(i) . The dimensions of K are -

A non-uniform electric field E=(5xhat i+3hat j)N/C goes through a cube of side length 2.0m oriented as shown. Then,