Find the roots of the following equation `4x^2+4b x-(a^2-b^2)=0` by the method of completing the square.

Explanation

Given

`4x^2+4b x-(a^2-b^2)=0`

`x^2+b x-(a^2-b^2)/4=0`

`x^2+2(b/2) x=(a^2-b^2)/4`

`x^2+2(b/2) x+(b/2)^2=(b/2)^2+(a^2-b^2)/4`

`(x+b/2)^2=a^2/4`

`(x+b/2)=a/2`

`x=(-b-a)/2,(-b+a)/2`

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