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If x=asinthetaa n dy=btantheta, then pro...

If `x=asinthetaa n dy=btantheta,` then prove that `(a^2)/(x^2)-(b^2)/(y^2)=1`

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Given
L.H.S
`(a^2)/(x^2)-(b^2)/(y^2)`
=`(a^2)/(a^2sin^2theta)-(b^2)/(a^2tan^2theta)`
=`(1)/(sin^2theta)-(1)/(tan^2theta)`
=`cosec^2theta-cot^2theta`
=`1`=R.H.S
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