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If the point P(2,2) is equidistant from ...

If the point `P(2,2)` is equidistant from the points `A(-2, k)a n dB(-2k ,-3)` , find `kdot` Also, find the length of AP.

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Given
Point P(2,2) is equidistant from the two points A(−2,k) and B(−2k,−3)
`PA=PB or PA^2=PB^2 `
`(2+2)^2+(2−k)^2=(2+2k)^2(2+3)^2 `
`4^2+4−4k+k^2=4+8k+4k^2+5^2`
...
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