If A&B are two events & `P(B) != 1`. Prove that `P(A//bar(B)) =(P(A) - P(A nn B))//(1 - P(B))`.

If A and B are two events and P(B)!=1 prove that,P[(A)/(B^(c))]=(P(A)-(P(A nn B)))/(1-P(B)) Hence,deduce that.P(A nn B)>P(A)+P(B)-1

If A and B are two events and P(B) ne 1 , prove that, P(A//B^(c ))=(P(A)-P(A cap B))/(1-P(B)) Hence, deduce that, P(A cap B) gt P(A) +P(B)-1 .

For two events A and B [with P(B)ne 0 ], show that P(A//bar B)= P(A) . (1-P(B//A))/(1-P(B))

For any two events A and B, show that, P(A uu B) = P(A) + P(B) - P(A nn B) .

If A o* B are two events then P{(A nnbar(B))uu(bar(A)nn B)}=(i)P(A uu B)-P(A nn B)(ii)P(A uu B)+P(A nn B)( iii) P(A)+P(B)(iv)P(A)+P(B)+P(A nn B)

If A and B are two events and P(A) = (3)/(8) . P(B) =(1)/(2), P(A nn B) = (1)/(4) then P(A uu B) =

If A and B are two events and P(A) = (3)/(8) . P(B) =(1)/(2), P(A nn B) = (1)/(4) then P(A uu B) =

If A and B are two events such that P(A)=(1)/(4), P(B)=(1)/(2) and P(A nn B)=(1)/(8) , find P(A' nn B')

If A and B are two events such that P(A) = (1)/(2) , P(B) = (1)/(3) and P(A nn B) = (1)/(4), then find (i) P(bar A//B) . (ii) P(B//A) .