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If xsin^3theta+ycos^3theta=sinthetacosth...

If `xsin^3theta+ycos^3theta=sinthetacostheta `and `xsintheta=ycostheta,` prove that `x^2+y^2=1`

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Given
`xsin^3theta+ycos^3theta=sinthetacostheta`
`(xsintheta)sin^2theta+(ycostheta)cos^2theta=sinthetacostheta`
`(xsintheta)sin^2theta+(xsintheta)cos^2theta=sinthetacostheta`
so,`xsintheta=sinthetacostheta`
`x=costheta`
Again,` ycostheta=xsintheta`
...
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