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If p , qr are real and p!=q , then show ...

If `p , qr` are real and `p!=q` , then show that the roots of the equation `(p-q)x^2+5(p+q)x-2(p-q=0` are real and unequal.

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To show that the roots of the equation \((p - q)x^2 + 5(p + q)x - 2(p - q) = 0\) are real and unequal, we will use the concept of the discriminant of a quadratic equation. ### Step-by-Step Solution: 1. **Identify the coefficients**: The given quadratic equation is in the form \(Ax^2 + Bx + C = 0\), where: - \(A = p - q\) - \(B = 5(p + q)\) ...
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