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Find the equation of the chord of the ci...

Find the equation of the chord of the circle `x^(2)+y^(2)+6x+8y-11=0,` whose midpoint is `(1,-1)`

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STATEMENT-1 : The equation of chord of circle x^(2) + y^(2) - 6x + 10y - 9 = 0 , which is be bisected at (-2, 4) must be x + y = 2. and STATEMENT-2 : The equation of chord with mid-point (x_(1), y_(1)) to the circle x^(2) + y^(2) = r^(2) is xx_(1) + yy_(1) = x_(1)^(2) + y^(2) .