If the area of the triangle having vertices `(a+1,0)(a-1,0)` and `(a,sqrt(3))` is `k sqrt(3)` ,then the value of "K" is

If the area of the triangle having vertices (2,-6) (5,4) and (k,4) is 35 sq. units , then find the value of k.

If the area of triangle having vertices (2,-5),(5,4) and (k,4) is 35 sq. units , then find the value of k.

Inradius of the triangle with vertices (1,1), (-1,-1), (-sqrt3, sqrt3) is

The area of a triangle with vertices (-3,0) , (3,0) and (0,k) is 9 sq. Units. Then , then value of k will be

The incetre of the triangle with vertices (1,sqrt(3)),(0,0) and (2,0) is

If the area of a triangle with vertices (- 3, 0), (3, 0) and (0, k) is 9 sq unit, then what is the value of k? (a)3 (b)6 (c)9 (d)12

Area of the triangle ABC with vertices (1,7),(-1,2) and (3,k) is 10 square units then sum of possible values of k is

If the area of triangle with vertices (-3,0), (3,0) and (0,k) is 9 sq . units then the value of k is