The displacement -time equation of a particle moving along x -axis is `x=(t^(3))/(3)-(t^(2))/(2)+20`The acceleration -velocity equation of the particle is `a^(2)=KV+1` Then the value of K is

The displacement of a particle moving along x-axis is given by : x = a + bt + ct^2 The acceleration of the particle is.

The displacement 'x' of a particle moving along a straight line at time t is given by x=a_(0)+a_(1)t+a_(2)t^(2) . The acceleration of the particle is :-

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.

Displacement-time equation of a particle moving along x-axis is x=20+t^3-12t (SI units) (a) Find, position and velocity of particle at time t=0. (b) State whether the motion is uniformly accelerated or not. (c) Find position of particle when velocity of particle is zero.

If the velocity of a paraticle moving along x-axis is given as v=(4t^(2)+3t=1)m//s then acceleration of the particle at t=1sec is :

The displacement x of a particle along a straight line at time t is given by : x = a_(0) + (a_(1) t)/(2) + (a_(2))/(3) t^(2) . The acceleration of the particle is

The displacement (in metre) of a particle moving along X-axis is given by x=18t+5t^(2) . The average acceleration during the interval t_(1)=2s and t_(2)=4s is

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is