Using quadratic formula, solve the following equation for `x:` `a b x^2+(b^2-a c)x-b c=0`

Explanation

Given:

`abx^2+(b^2-ac)x−bc=0`


`=>abx^2+b^2x−acx−bc=0
`

`=>bx(ax+b)−c(ax+b)=0`

`=>(bx−c)(ax+b)=0`

So,`(bx−c)=0 or (ax+b)=0`

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