If the point `(x ,4)` lies on a circle whose centre is at the origin and radius is 5, then `x=` `+-5` (b) `+-3` (c) `0` (d) `14`

Explanation

Given,

center`=(0,0)` and
radius`(r)=5`

equation of circle,

`(x-0)^2+(y-0)^2=5^2`

`x^2+y^2=25`


Now,

`p(x,4)` lies on it,

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