The length of a line segment is of 10 units and the coordinates of one end-point are `(2,-3)dot` If the abscissa of the other end is 10, find the ordinate of the other end.

Explanation

Given, Point `=(2,−3)`

and let other point `=(10,b)`

by distance formula,


`sqrt((10−2)^2+(b+3)^2)​=10
`

`=>sqrt(8^2+(b^2+9+6b))​=10
`

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