In an A.P., the sum of first `n` terms is `(3n^2)/2+(5n)/2dot` Find its 25th term.

Explanation

Let the sum of `n` terms be given by `S_n`

so

`S_n=(3n^2)/2+(5n)/2`

`S_1=(3(1)^2)/2+(5(1))/2
=3/2+5/2=4`

So `1^(st)` term is `4` let it be a

Now,

`S_2=(3(2)^2)/2+(5(2))/2
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