The sum of the first `p , q , r` terms of an A.P. are `a , b , c` respectively. Show that `a/p(q-r)+b/q(r-p)+c/r(p-q)=0`

Explanation

Given, sum of first `p, q, r` term of an `A.P`
are `a, b, c`


So,

` S_p​=a`
`=>p/​2[2A+(p−1)D]=a`

Similarly,` S_q​=b`
`=>q/2​[2A+(q−1)D]=b`

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