Evaluate : `intdx/sqrt((x-1)(2-x))` by the substitution `x=1+sin^2theta`. Hence, find the value of `int_1^2dx/sqrt((x-1)(2-x))`

Evaluate: int(dx)/(sqrt((x-1)(2-x))) by the substitution x=1+sin^(2)theta . Hence, find the value of int_(1)^(2)(dx)/(sqrt((x-1)(2-x)))

Evaluate: intdx/sqrt ((x-1)(x-2))

Evaluate: intdx/sqrt ((x-1)(x-2))

Evaluate: intdx/sqrt(1+x-x^2)

Evaluate: int1/(sqrt((x-1)(x-2)))dx

Evaluate: int1/(sqrt((x-1)(x-2)))dx

Evaluate: intdx/(sqrt(x^2+x+1))

Evaluate: int1/(x+sqrt(x^2-x+1))dx

Evaluate: int1/(x+sqrt(x^2-x+1))dx

Evaluate: intdx/((1+x^2)sqrt(1-x^2))