If mth term of an AP is 1/n and its nth term is 1/m , then show that its (mn)th term is 1

Explanation

Let `a` be first term and `d` be the common difference of an `AP`

`m^(th) term=1/n`

so,

`a_m​=a+(m−1)d=1/n .........(1)`

`n^(th) term=1/m`

`a_n​=a+(n−1)d=1/m ........(2)`


Subtract `(2)` from `(1)`

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