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If 5-(3x^2)/4lt=f(x)lt=5+(2x^3)/9AAx!=0 ...

If `5-(3x^2)/4lt=f(x)lt=5+(2x^3)/9AAx!=0` in `[-1, 1]` then `lim_(x->0) f(x)=` (i)`17/4` (ii)`47/9` (iii)`5` (iv) none of these

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