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" 5) "x=a(2t+sin2t),y=a(1-cos2t)...

" 5) "x=a(2t+sin2t),y=a(1-cos2t)

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Find (dy)/(dx) when : x=a(2t+sin2t), y=a(1-cos2t)

The coordinate of a moving point at time t are given by x=a(2t+sin2t),y=a(1-cos2t) Prove that acceleration is constant.

x=sqrt(sin 2t),y=sqrt(cos 2 t)

x=sin t, y= cos 2t.

x = "sin" t, y = "cos" 2t

x = "sin" t, y = "cos" 2t

If x=a(cos2t+2t sin2t) and y=a(sin2t-2t cos2t), then find (d^(2)y)/(dx^(2))

If x=a(cos2t+2tsin2t) and y=a(sin2t-2tcos2t) , then find (dy)/(dx) .

If (x=a sin (2t)(1+cos(2t)) and (y=b cos (2t) (1- cos(2t)) , then show that ((dy/dx)_(t=pi/4) =b/a) .