" fi "(5)/(2)pi=(25)/(4)

(5)/(2)x=(25)/(4)

sin^(2)(pi)/(4)+sin^(2)(3 pi)/(4)+sin^(2)(5 pi)/(4)+sin^(2)(7 pi)/(4)=2

If 4cos^(2)theta=3 then theta =---- 1) (pi)/(6),(5 pi)/(6) 2) (pi)/(4),(3 pi)/(4) 3) (pi)/(3),(2 pi)/(3) 4) +-(pi)/(2)

sin "" (pi)/(5) sin "" (2pi)/(5) sin ""(4pi)/(5) sin""(3pi)/(5) = (5)/(16).

evaluvate int_(5/2)^5(sqrt((25-x^2)^3))/(x^4)dx (A) pi/6 (b) (2pi)/3 (5pi)/6 (d) pi/3

int_(5/2)^5(sqrt((25-x^2)^3))/(x^4)dx is equal to (a) pi/6 (b) (2pi)/3 (c) (5pi)/6 (d) pi/3

Find the values of k so that the function fis continuous at the indicated point in f(x)={((k cos x)/(pi-2x),quad if x!=(pi)/(2)),(3 if x=(pi)/(2)) at x=(pi)/(2)

cos^(2)""(pi)/(5)+ sin^(2)""(4pi)/(5)=

Evalute : "sin"^(2)(pi)/(4) + "cos"^(2) (3pi)/(4)+"cos"^(2)(5pi)/(4)+"sin"^(2)(7pi)/(4).