The sum of the first `p , q , r` terms of an A.P. are `a , b , c` respectively. Show that `a/p(q-r)+b/q(r-p)+c/r(p-q)=0`

Explanation

To solve the problem, we need to show that

\[ \frac{a}{p(q-r)} + \frac{b}{q(r-p)} + \frac{c}{r(p-q)} = 0 \]

Given that the sum of the first \( p \), \( q \), and \( r \) terms of an arithmetic progression (A.P.) are \( a \), \( b \), and \( c \) respectively, we can use the formula for the sum of the first \( n \) terms of an A.P.:

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