["Solve the following:"],[" In the fig,seg "SP perp" side "YK" and "],[seg YT perp seg" SK.If "SP=6,YK=13,],[YT=5" and "TK=12," then "],[" find "A(Delta SYK):A(Delta YTK)]

In the figure seg SP_|_ side YK, and seg Yt_|_ side SK. If SP=6, YK=13, YT=5 and TK=12 , thenfidn A(DeltaSYK):A(DeltaYTK) .

(A) Complete any two out of three activites : In the figure , seg SP bot side YK . Seg YT bot side SK . If SP = 6 , YK = 13, YT = 5 and TK = 12 then complete the following activity to find A (Delta SYK ) : A (Delta YTK) The ratio of the areas of the two Deltas is equal to the ratio of the products of their square and the corresponding heights :. (A(Delta SYK))/(A (Delta YTK)) = (square xxSP)/(TK xx TY) = (13 xx 6) /(12 xx square ) = square /square

In the following figure seg PS_|_ seg RQ , seg QT_|_ seg PR . If RQ=6,PS=6 and PR=12 , then find the QT .

In the following figure, seg DH bot seg EF and seg GK bot seg EF. If DH = 6 cm, GK = 10 cm and A(Delta DEF) = 150 cm^(2) , then find : i. EF ii. A(Delta GEF) iii. A( square DFGE).

In the following figure set PS_|_ seg RQ ,set QT_|_ set PR. If RQ=6,PS=6 and PR=12 , then find the QT.

In the figure A-D-C and B-E-C. "seg "DE||"side " AB. "if " AD=5, DC=3, BC=6.4 then find BE.

Solve the following sub questions: in Delta PQR, angle PQR = 90^(@) "seg" QS bot "hypotenuse" PR, PS = 16 , RS = 9 "find" QS

Solve the any one of following sub questions: In Delta PQR, "seg" PM "is a median" PM = 10 and PQ^(2) + PR^(2) = 328 "then find" QR

In DeltaABC,angleB=90^(@),"seg "DEbot"side " AC. AD=6,AB=12, AC=18, , then find AE.