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If cos A / cos B =m and cos A/ sin B= n ...

If `cos A / cos B =m` and `cos A/ sin B= n` then prove that `(m^2 + n^2) cos^2 B = n^2`

Text Solution

Verified by Experts

Given,
`m=cosA/cosB`​ and `n=cosA/sinB`
​ so `(m^2+n^2)cos^2B`
=`(cos^2A/cos^2B​+cos^2A/sin^2B​)cos^2B`
=`cos^2A((sin^2B+cos^2B)/(cos^2Bsin^2B​))cos^2B`
=`cos^2A xx 1/sin^2B​`
...
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