A wire of length `5m` is twisted through `30^(0)` at free end If the radius of wire is `1mm` , the shearing strain in the wire is

A wire of length 1 m and radius 1mm is subjected to a load. The extension is x .The wire is melted and then drawn into a wire of square cross - section of side 2 mm Its extension under the same load will be

A steel wire of length 3.0m is stretched through 3.0 mm. the cross-sectional area of the wire is 5.0mm^(2) . Calculate the elastic potential energy stroed in the wire in the stretched condition. Young's modulus of steel is 2.0 xx 10^(11) Nm^(-2) .

A wire suspended vertically is stretched by a 20 kgf. applied to its free end. The increase in length of the wire is 2 mm. The energy stored in the wire is (g=10ms^(-2)) :

When a wire is twisted, the strain produced in it is

A wire of length 1 m and radius 1 mm is welded to another wire of length 2 m and radius 2 mm the free end of the first is clamped and aload of 5kg ispplied at the free end of the second wire . What is the total increase of the compound wire ? (Y of both wires =2xx10^(11) ""Nm^(-2) )

A wire of length 5 m is stretched by 1 mm by a force of 1 N. The value of energy (in mJ) stored in the wire is

A wire made of aluminum having resistivity rho = 2.8 xx10^(-8) Omega - m with a circular cross - section and has a radius of 2xx10^(-3) m. A current of 5 A flows through the wire . If the voltage difference between the ends is 1 V , the length of the wire in m is

A silver wire of length 2m and radius 1mm is joined in series with an iron wire of length "4m" and radius "3mm" and a current is passed through the wires. The ratio of the current density in the silver and iron wires is

A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. If the increase in length is 1.0 mm, the increase in energy of the wire will be

A wire of length 100 m is tightly wounded on a hollow tube of radius 5mm and length 1 m. A current of 1 A is flowing in the wire. Then magnetic field strength inside the tube will be :-