`cos m theta-sin n theta=0`

Solve that equation : sin m theta+sin n theta=0

cos m theta=sin n theta then theta=

If m and n are positive integers satisfying 1+cos2 theta+cos4 theta+cos6 theta+cos8 theta+cos10 theta=(cos m theta*sin n theta)/(sin theta) then (m+n) is equal to

If cos ec theta-sin theta=m and sec theta-cos theta,=n, eliminate theta

if cos ec theta-sin theta=m and sec theta-cos theta=n, eliminate theta

[(1 + cos theta + i sin theta) / (sin theta + i (1 + cos theta))] ^ (4) = cos n theta + i sin n theta

(cos theta + i sin theta) ^ (n) = cos n theta + i sin n theta

If 5 cos theta -12 sin theta =0 , the value of (2 sin theta +cos theta )/(cos theta - sin theta ) यदि 5 cos theta -12 sin theta =0 , है, तो (2 sin theta +cos theta )/(cos theta - sin theta ) का मान ज्ञात करें |

If A=[cos theta i sin theta i sin theta cos theta], then prove by principle of mathematical induction that A^(n)=[cos n theta i sin n theta i sin n theta cos n theta] for all n in N.

Prove that ((1+cos theta+i sin theta)/(1+cos theta-i sin theta))^(n)=cos n theta+i sin n theta