Find the angle between the line `(x+1)/2=y/3=(z-3)/6`and the plane `10 x + 2y -11 z = 3`.

Explanation

To find the angle between the line given by the equation \((x+1)/2 = y/3 = (z-3)/6\) and the plane defined by the equation \(10x + 2y - 11z = 3\), we can follow these steps:

### Step 1: Convert the line equation to vector form

The line can be expressed in parametric form. Let \( t \) be the parameter. We can write:
- \( x = 2t - 1 \)
- \( y = 3t \)
- \( z = 6t + 3 \)
...