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In how many ways can 10 examination pape...

In how many ways can 10 examination papers be arranged so that the best and worst papers never come together?

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Number of ways of arranging 10 exam papers =10P10​=10! ways. Let us consider the best and worst paper as one group and all other papers as different.. The number of ways of arranging 9 groups is `9_(P_9)​=9!` ways.
Best and worst paper can themselves be arranged in `2_(P_2)​=2` ways
Total number of arrangements with best and worst papers together =`9!xx2 `ways.
Hence, total number of arrangements with them not together =`10!−2xx9!`
=`8×9!` ways.
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