if `tantheta+cottheta=x` then `tan^4theta+cot^4theta`

if tan theta+cot theta=x then tan^(4)theta+cot^(4)theta

If tantheta+cottheta=5 , then tan^(2)theta+cot^(2)theta is

If Tan theta + Cot theta = 3 then Tan^(4)theta+Cot^(4)theta =

If 3tantheta=cot theta then theta =

tantheta-cottheta+2tan2thet+4tan4theta+8cot8theta=0

Eliminate theta "from the equation" m= tantheta +cottheta and n= tan theta - cot theta .

Statement (A) : If tantheta+cottheta=2 , then for all n epsilon N, tan^(n)theta+cot^(n)theta=2 Reason (R ) : For all n epsilon N, tan theta+cot theta=tan^(n)theta+cot^(n)theta

The smallest value of 3(tan^(2)theta+cot^(2)theta) - 8(tantheta + cottheta)+10, theta in (0,pi/2) can be

The smallest value of 3(tan^(2)theta+cot^(2)theta) - 8(tantheta + cottheta)+10, theta in (0,pi/2) can be