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Incident wave y= A sin (ax + bt+ pi/2) i...

Incident wave `y= A sin (ax + bt+ pi/2)` is reflected by an obstacle at x = 0 which reduces intensity of reflected wave by 36%. Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by
`y= -1.6 sin ax sin bt + cA cos (bt + ax)`
where A, a, b and c are positive constants.
1. Amplitude of reflected wave is

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Incident wave y= A sin (ax + bt+ pi/2) is reflected by an obstacle at x = 0 which reduces intensity of reflected wave by 36%. Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by y= -1.6 sin ax sin bt + cA cos (bt + ax) where A, a, b and c are positive constants. 2. Value of c is

Incident wave y= A sin (ax + bt+ pi/2) is reflected by an obstacle at x = 0 which reduces intensity of reflected wave by 36%. Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by y= -1.6 sin ax sin bt + cA cos (bt + ax) where A, a, b and c are positive constants. 2. Value of c is

Incident wave y= A sin (ax + bt+ pi/2) is reflected by an obstacle at x = 0 which reduces intensity of reflected wave by 36%. Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by y= -1.6 sin ax sin bt + cA cos (bt + ax) where A, a, b and c are positive constants. 3. Position of second antinode is

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