A manometer attached to a flask contains with ammonia gas have no difference in mercury level initially as shown in diagram. After sparking into the flask, ammonia is partially dissociated as `2NH_(3)" (g)"rarr N_(2)" (g)"+3H_(2)" (g)"` now it have difference of 6 cm in mercury level in two columns, what is partial pressure of `H_(2)" (g)"` at equilibrium?
Ammonia gas at 76 cm Hg pressure was connected to a manometer. After sparking in the flask, ammonia is partially dissociated as follows : 2NH_(3) (g) hArr N_(2) (g) + 3H_(2) (g) the level in the mercury column of the manometer was found to show the difference of 18 cm. What is the partial pressure of H_(2) (g) at equilibrium ?
The enthalpy of formation of ammonia is -46.0 KJ mol^(-1) . The enthalpy change for the reaction 2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g) is :
An open ended mercury mnometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Initially manometer shows no difference in mercury level in both columns as shown in diagram. After sparking A dissociates according to following reaction: 2A(g)rarr3B(g)+2C(g) ltbr. If pressure of Gas A decreases to 0.8 atm. Then: (Assume temperature to be constant at 300K)
A open ended mercury manometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Initially manometer shows no difference in mercury level in both columns as shown in diagram. After sparking 'A' dissociates according to following reaction A(g)rarrB(g)+3C(g) If pressure of Gas "A" dissociates to 0.9 atm, then (Assume temperature to be constant and is 300 K)
A monometer contains a liquid of density 5.44g//cm^(3) is attached to a flask containing gas 'A' as follows The initial pressure of gas A in th flask is:
Which of the following is correct for the reaction? N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g)
Vapour density of the equilibrium mixture of the reaction 2NH_(3)(g)hArrN_(2)(g) + 3H_(2) (g) is 6.0 Percent dissociation of ammonia gas is :
Ammonia is prepared as 3H_(2)(g) + N_(2)(g) to 2NH_(3)(g) What should be the sign of DeltaS for this reaction? Explain.
