A mixture of `C_(2)H_(2)` and `C_(3)H_(8)` occupied a certain volume at 80 mm Hg. The mixture was completely burnt to `CO_(2)` and `H_(2)O(l)`. When the pressure of `Co_(2)` was found to be 230 mm Hg at the same temperature and volume, the mole fraction of `CO_(3)H_(8)` in the mixture is :
A
0.125
B
0.875
C
0.6
D
0.8
Text Solution
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The correct Answer is:
b
(b) Moles of `C_(2)H_(2)` and `C_(3)H_(8)` are a and b `underset(a)(C_(2)H_(2))+2.5O_(2)rarrunderset(2a)(2CO_(2))+H_(2)O` `underset(b)(C_(3)H_(8))+5O_(2)rarrunderset(3b)(3CO_(2))+4H_(2)O` `2a+3b prop 230` `a+b prop 80` `b prop70` `a prop 10` mole fraction`=(7)/(8)=0.875`
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