At STP a contains has 1 mole of `H_(2)` 2 mole `Ne,` 3 mole `O_(2)` and 4 mole `N_(2)`. Without changing total pressure if 2 mole of `O_(2)` is removed, the partial pressure of `O_(2)` will be decreased by
A
`26 %`
B
`40%`
C
`58.33%`
D
`66.66%`
Text Solution
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The correct Answer is:
c
(c) `P_(O_(2)=(3)/(10)xxP_(T),` After remiving 2 mole of `O_(2)` ` P'_(O_(2))=(1)/(8)xxP_(r)` Decrease in partial pressure of `O_(2)` `=((3P_(T))/(10)-(P_(T))/(8))/((3P_(T))/(10))xx100` `=58.33`
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