Let P and P_(s) be the partial pressure of water and saturated partial pressure of water vapours, then relative humidity is given by .
A sample of pure CuO was reduced with H_2 gas and H_(2)O formed was collected in a 44.8 L flask containing dry N_(2) . At 27^@C , the total pressure containing N_(2) and H_(2)O was 1.0 atm. The relative humidity in the flask was 80% The vapour pressure of water at 27^@C is 25 mm. How many grams of CuO was reduced?
For the equilibrium CuSO_(4)xx5H_(2)O(s)hArrCuSO_(4)xx3H_(2)O(s) + 2H_(2)O(g) K_(p) = 2.25xx10^(-4)atm^(2) and vapour pressure of water is 22.8 torr at 298 K. CuSO_(4) . 5H_(2)O(s) is efflorescent (i.e., losses water) when relative humidity is :
At 20^(@)C vapour pressure of H_(2)O(l) is recorded as 28.57m bar. The initial and final vapour pressure of H_(2)O(l) , if volume of container containing (H_(2)O(l) is increased from 5 litre to 10litre, are:
For equilibrium ZnSO_(4).7H_(2)O(s)hArrZnSO_(4).2H_(2)O(s)+5H_(2)O(g) K_(P)=56.25xx10^(-10) atm^(5) and vapour pressure of water is 22.8 torr at 298K.ZnSO_(4).7H_(2)O(s) is efflorescent (lose water) when relative humidity is [5sqrt56.25=2.23]
How much water vapour is contained in a cubic room of 4m along an edge if the relative humidity 1s 50% water at 27^(@)C The vapour pressure of water at 27^(@)C is 26.7 torr (The relative humidity expresses the partial pressure of water as a per cent of water vapour pressure) .
CuSO_(4).5H_(2)O(s)hArrCuSO_(4). 3H_(2)O(s)+2H_(2)O(g), K_(p)=4xx10^(-4)atm^(2) If the vapour pressure of water is 38 toor then percentage of relatative humidity is :(Assume all data at constant temperture)
